6z+28=2z+16

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Solution for 6z+28=2z+16 equation: 



6z+28=2z+16

We move all terms to the left:

6z+28-(2z+16)=0

We get rid of parentheses

6z-2z-16+28=0

We add all the numbers together, and all the variables

4z+12=0

We move all terms containing z to the left, all other terms to the right

4z=-12

z=-12/4

z=-3

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