6z+3/5=7z+2/5

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Solution for 6z+3/5=7z+2/5 equation:



6z+3/5=7z+2/5
We move all terms to the left:
6z+3/5-(7z+2/5)=0
We add all the numbers together, and all the variables
6z-(+7z+2/5)+3/5=0
We get rid of parentheses
6z-7z-2/5+3/5=0
We multiply all the terms by the denominator
6z*5-7z*5-2+3=0
We add all the numbers together, and all the variables
6z*5-7z*5+1=0
Wy multiply elements
30z-35z+1=0
We add all the numbers together, and all the variables
-5z+1=0
We move all terms containing z to the left, all other terms to the right
-5z=-1
z=-1/-5
z=1/5

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