6z+30-4z-4=9(z+3)

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Solution for 6z+30-4z-4=9(z+3) equation: 



6z+30-4z-4=9(z+3)

We move all terms to the left:

6z+30-4z-4-(9(z+3))=0

We add all the numbers together, and all the variables

2z-(9(z+3))+26=0



We calculate terms in parentheses: -(9(z+3)), so:

9(z+3)

We multiply parentheses

9z+27

Back to the equation:

-(9z+27)



We get rid of parentheses

2z-9z-27+26=0

We add all the numbers together, and all the variables

-7z-1=0

We move all terms containing z to the left, all other terms to the right

-7z=1

z=1/-7

z=-1/7

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