6z+36=3(2z+12)

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Solution for 6z+36=3(2z+12) equation: 



6z+36=3(2z+12)

We move all terms to the left:

6z+36-(3(2z+12))=0



We calculate terms in parentheses: -(3(2z+12)), so:

3(2z+12)

We multiply parentheses

6z+36

Back to the equation:

-(6z+36)



We get rid of parentheses

6z-6z-36+36=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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