6z+3=-3z2

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Solution for 6z+3=-3z2 equation: 



6z+3=-3z^2

We move all terms to the left:

6z+3-(-3z^2)=0

We get rid of parentheses

3z^2+6z+3=0

a = 3; b = 6; c = +3;
Δ = b2-4ac
Δ = 62-4·3·3
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{-6}{6}=-1$

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