6z+48=8z+40

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Solution for 6z+48=8z+40 equation: 



6z+48=8z+40

We move all terms to the left:

6z+48-(8z+40)=0

We get rid of parentheses

6z-8z-40+48=0

We add all the numbers together, and all the variables

-2z+8=0

We move all terms containing z to the left, all other terms to the right

-2z=-8

z=-8/-2

z=+4

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