6z+5(4-z)=-(z-3)+5

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Solution for 6z+5(4-z)=-(z-3)+5 equation: 



6z+5(4-z)=-(z-3)+5

We move all terms to the left:

6z+5(4-z)-(-(z-3)+5)=0

We add all the numbers together, and all the variables

6z+5(-1z+4)-(-(z-3)+5)=0

We multiply parentheses

6z-5z-(-(z-3)+5)+20=0



We calculate terms in parentheses: -(-(z-3)+5), so:

-(z-3)+5

We get rid of parentheses

-z+3+5

We add all the numbers together, and all the variables

-1z+8

Back to the equation:

-(-1z+8)



We add all the numbers together, and all the variables

z-(-1z+8)+20=0

We get rid of parentheses

z+1z-8+20=0

We add all the numbers together, and all the variables

2z+12=0

We move all terms containing z to the left, all other terms to the right

2z=-12

z=-12/2

z=-6

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