6z+5(4-z)=-(z-5)+9

Solution for 6z+5(4-z)=-(z-5)+9 equation:

6z+5(4-z)=-(z-5)+9

We move all terms to the left:

6z+5(4-z)-(-(z-5)+9)=0

We add all the numbers together, and all the variables

6z+5(-1z+4)-(-(z-5)+9)=0

We multiply parentheses

6z-5z-(-(z-5)+9)+20=0


We calculate terms in parentheses: -(-(z-5)+9), so:

-(z-5)+9

We get rid of parentheses

-z+5+9

We add all the numbers together, and all the variables

-1z+14

Back to the equation:

-(-1z+14)


We add all the numbers together, and all the variables

z-(-1z+14)+20=0

We get rid of parentheses

z+1z-14+20=0

We add all the numbers together, and all the variables

2z+6=0

We move all terms containing z to the left, all other terms to the right

2z=-6

z=-6/2

z=-3