6z+8=6(z+2)-4=

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Solution for 6z+8=6(z+2)-4= equation: 



6z+8=6(z+2)-4=

We move all terms to the left:

6z+8-(6(z+2)-4)=0



We calculate terms in parentheses: -(6(z+2)-4), so:

6(z+2)-4

We multiply parentheses

6z+12-4

We add all the numbers together, and all the variables

6z+8

Back to the equation:

-(6z+8)



We get rid of parentheses

6z-6z-8+8=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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