6z-1+4z+12=10z-5+12z-1

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Solution for 6z-1+4z+12=10z-5+12z-1 equation: 



6z-1+4z+12=10z-5+12z-1

We move all terms to the left:

6z-1+4z+12-(10z-5+12z-1)=0

We add all the numbers together, and all the variables

6z+4z-(22z-6)-1+12=0

We add all the numbers together, and all the variables

10z-(22z-6)+11=0

We get rid of parentheses

10z-22z+6+11=0

We add all the numbers together, and all the variables

-12z+17=0

We move all terms containing z to the left, all other terms to the right

-12z=-17

z=-17/-12

z=1+5/12

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