6z-12=6(z+12)

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Solution for 6z-12=6(z+12) equation: 



6z-12=6(z+12)

We move all terms to the left:

6z-12-(6(z+12))=0



We calculate terms in parentheses: -(6(z+12)), so:

6(z+12)

We multiply parentheses

6z+72

Back to the equation:

-(6z+72)



We get rid of parentheses

6z-6z-72-12=0

We add all the numbers together, and all the variables

-84!=0

There is no solution for this equation

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