6z-5(z+1)=2(z-5)-z

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Solution for 6z-5(z+1)=2(z-5)-z equation:


Simplifying
6z + -5(z + 1) = 2(z + -5) + -1z

Reorder the terms:
6z + -5(1 + z) = 2(z + -5) + -1z
6z + (1 * -5 + z * -5) = 2(z + -5) + -1z
6z + (-5 + -5z) = 2(z + -5) + -1z

Reorder the terms:
-5 + 6z + -5z = 2(z + -5) + -1z

Combine like terms: 6z + -5z = 1z
-5 + 1z = 2(z + -5) + -1z

Reorder the terms:
-5 + 1z = 2(-5 + z) + -1z
-5 + 1z = (-5 * 2 + z * 2) + -1z
-5 + 1z = (-10 + 2z) + -1z

Combine like terms: 2z + -1z = 1z
-5 + 1z = -10 + 1z

Add '-1z' to each side of the equation.
-5 + 1z + -1z = -10 + 1z + -1z

Combine like terms: 1z + -1z = 0
-5 + 0 = -10 + 1z + -1z
-5 = -10 + 1z + -1z

Combine like terms: 1z + -1z = 0
-5 = -10 + 0
-5 = -10

Solving
-5 = -10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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