6z-5(z+1)=4(z-5)-3z

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Solution for 6z-5(z+1)=4(z-5)-3z equation:


Simplifying
6z + -5(z + 1) = 4(z + -5) + -3z

Reorder the terms:
6z + -5(1 + z) = 4(z + -5) + -3z
6z + (1 * -5 + z * -5) = 4(z + -5) + -3z
6z + (-5 + -5z) = 4(z + -5) + -3z

Reorder the terms:
-5 + 6z + -5z = 4(z + -5) + -3z

Combine like terms: 6z + -5z = 1z
-5 + 1z = 4(z + -5) + -3z

Reorder the terms:
-5 + 1z = 4(-5 + z) + -3z
-5 + 1z = (-5 * 4 + z * 4) + -3z
-5 + 1z = (-20 + 4z) + -3z

Combine like terms: 4z + -3z = 1z
-5 + 1z = -20 + 1z

Add '-1z' to each side of the equation.
-5 + 1z + -1z = -20 + 1z + -1z

Combine like terms: 1z + -1z = 0
-5 + 0 = -20 + 1z + -1z
-5 = -20 + 1z + -1z

Combine like terms: 1z + -1z = 0
-5 = -20 + 0
-5 = -20

Solving
-5 = -20

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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