6z-7=12+10(z+5)

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Solution for 6z-7=12+10(z+5) equation: 



6z-7=12+10(z+5)

We move all terms to the left:

6z-7-(12+10(z+5))=0



We calculate terms in parentheses: -(12+10(z+5)), so:

12+10(z+5)

determiningTheFunctionDomain
10(z+5)+12

We multiply parentheses

10z+50+12

We add all the numbers together, and all the variables

10z+62

Back to the equation:

-(10z+62)



We get rid of parentheses

6z-10z-62-7=0

We add all the numbers together, and all the variables

-4z-69=0

We move all terms containing z to the left, all other terms to the right

-4z=69

z=69/-4

z=-17+1/4

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