6z-7=2z+35

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Solution for 6z-7=2z+35 equation: 



6z-7=2z+35

We move all terms to the left:

6z-7-(2z+35)=0

We get rid of parentheses

6z-2z-35-7=0

We add all the numbers together, and all the variables

4z-42=0

We move all terms containing z to the left, all other terms to the right

4z=42

z=42/4

z=10+1/2

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