6z2+9z-4=0

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Solution for 6z2+9z-4=0 equation: 



6z^2+9z-4=0

a = 6; b = 9; c = -4;
Δ = b2-4ac
Δ = 92-4·6·(-4)
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{177}}{2*6}=\frac{-9-\sqrt{177}}{12}
$


$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{177}}{2*6}=\frac{-9+\sqrt{177}}{12}
$

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