6z=3z+2(7+5z)

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Solution for 6z=3z+2(7+5z) equation: 



6z=3z+2(7+5z)

We move all terms to the left:

6z-(3z+2(7+5z))=0

We add all the numbers together, and all the variables

6z-(3z+2(5z+7))=0



We calculate terms in parentheses: -(3z+2(5z+7)), so:

3z+2(5z+7)

We multiply parentheses

3z+10z+14

We add all the numbers together, and all the variables

13z+14

Back to the equation:

-(13z+14)



We get rid of parentheses

6z-13z-14=0

We add all the numbers together, and all the variables

-7z-14=0

We move all terms containing z to the left, all other terms to the right

-7z=14

z=14/-7

z=-2

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