6z=4(2z-7)

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Solution for 6z=4(2z-7) equation: 



6z=4(2z-7)

We move all terms to the left:

6z-(4(2z-7))=0



We calculate terms in parentheses: -(4(2z-7)), so:

4(2z-7)

We multiply parentheses

8z-28

Back to the equation:

-(8z-28)



We get rid of parentheses

6z-8z+28=0

We add all the numbers together, and all the variables

-2z+28=0

We move all terms containing z to the left, all other terms to the right

-2z=-28

z=-28/-2

z=+14

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