7(-10h-40)-50=10(3h-31)-50h

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Solution for 7(-10h-40)-50=10(3h-31)-50h equation: 



7(-10h-40)-50=10(3h-31)-50h

We move all terms to the left:

7(-10h-40)-50-(10(3h-31)-50h)=0

We multiply parentheses

-70h-(10(3h-31)-50h)-280-50=0



We calculate terms in parentheses: -(10(3h-31)-50h), so:

10(3h-31)-50h

We add all the numbers together, and all the variables

-50h+10(3h-31)

We multiply parentheses

-50h+30h-310

We add all the numbers together, and all the variables

-20h-310

Back to the equation:

-(-20h-310)



We add all the numbers together, and all the variables

-70h-(-20h-310)-330=0

We get rid of parentheses

-70h+20h+310-330=0

We add all the numbers together, and all the variables

-50h-20=0

We move all terms containing h to the left, all other terms to the right

-50h=20

h=20/-50

h=-2/5

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