7(-2-4r)+7r=-5(r+6)

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Solution for 7(-2-4r)+7r=-5(r+6) equation: 



7(-2-4r)+7r=-5(r+6)

We move all terms to the left:

7(-2-4r)+7r-(-5(r+6))=0

We add all the numbers together, and all the variables

7(-4r-2)+7r-(-5(r+6))=0

We add all the numbers together, and all the variables

7r+7(-4r-2)-(-5(r+6))=0

We multiply parentheses

7r-28r-(-5(r+6))-14=0



We calculate terms in parentheses: -(-5(r+6)), so:

-5(r+6)

We multiply parentheses

-5r-30

Back to the equation:

-(-5r-30)



We add all the numbers together, and all the variables

-21r-(-5r-30)-14=0

We get rid of parentheses

-21r+5r+30-14=0

We add all the numbers together, and all the variables

-16r+16=0

We move all terms containing r to the left, all other terms to the right

-16r=-16

r=-16/-16

r=1

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