7(-3+2y)=8(3y-2)

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Solution for 7(-3+2y)=8(3y-2) equation: 



7(-3+2y)=8(3y-2)

We move all terms to the left:

7(-3+2y)-(8(3y-2))=0

We add all the numbers together, and all the variables

7(2y-3)-(8(3y-2))=0

We multiply parentheses

14y-(8(3y-2))-21=0



We calculate terms in parentheses: -(8(3y-2)), so:

8(3y-2)

We multiply parentheses

24y-16

Back to the equation:

-(24y-16)



We get rid of parentheses

14y-24y+16-21=0

We add all the numbers together, and all the variables

-10y-5=0

We move all terms containing y to the left, all other terms to the right

-10y=5

y=5/-10

y=-1/2

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