7(-3-2)+(1-x)=9(2x-5)-3(3x-5)

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Solution for 7(-3-2)+(1-x)=9(2x-5)-3(3x-5) equation: 



7(-3-2)+(1-x)=9(2x-5)-3(3x-5)

We move all terms to the left:

7(-3-2)+(1-x)-(9(2x-5)-3(3x-5))=0

We add all the numbers together, and all the variables

(-1x+1)-(9(2x-5)-3(3x-5))+7(-5)=0

We add all the numbers together, and all the variables

(-1x+1)-(9(2x-5)-3(3x-5))-35=0

We get rid of parentheses

-1x-(9(2x-5)-3(3x-5))+1-35=0



We calculate terms in parentheses: -(9(2x-5)-3(3x-5)), so:

9(2x-5)-3(3x-5)

We multiply parentheses

18x-9x-45+15

We add all the numbers together, and all the variables

9x-30

Back to the equation:

-(9x-30)



We add all the numbers together, and all the variables

-1x-(9x-30)-34=0

We get rid of parentheses

-1x-9x+30-34=0

We add all the numbers together, and all the variables

-10x-4=0

We move all terms containing x to the left, all other terms to the right

-10x=4

x=4/-10

x=-2/5

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