7(-3a-8)+9a=-10(10-a)

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Solution for 7(-3a-8)+9a=-10(10-a) equation: 



7(-3a-8)+9a=-10(10-a)

We move all terms to the left:

7(-3a-8)+9a-(-10(10-a))=0

We add all the numbers together, and all the variables

7(-3a-8)+9a-(-10(-1a+10))=0

We add all the numbers together, and all the variables

9a+7(-3a-8)-(-10(-1a+10))=0

We multiply parentheses

9a-21a-(-10(-1a+10))-56=0



We calculate terms in parentheses: -(-10(-1a+10)), so:

-10(-1a+10)

We multiply parentheses

10a-100

Back to the equation:

-(10a-100)



We add all the numbers together, and all the variables

-12a-(10a-100)-56=0

We get rid of parentheses

-12a-10a+100-56=0

We add all the numbers together, and all the variables

-22a+44=0

We move all terms containing a to the left, all other terms to the right

-22a=-44

a=-44/-22

a=+2

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