7(-3j+2)=8(3j-2)

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Solution for 7(-3j+2)=8(3j-2) equation: 



7(-3j+2)=8(3j-2)

We move all terms to the left:

7(-3j+2)-(8(3j-2))=0

We multiply parentheses

-21j-(8(3j-2))+14=0



We calculate terms in parentheses: -(8(3j-2)), so:

8(3j-2)

We multiply parentheses

24j-16

Back to the equation:

-(24j-16)



We get rid of parentheses

-21j-24j+16+14=0

We add all the numbers together, and all the variables

-45j+30=0

We move all terms containing j to the left, all other terms to the right

-45j=-30

j=-30/-45

j=2/3

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