7(-3y+2)=28(3y-2)

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Solution for 7(-3y+2)=28(3y-2) equation: 



7(-3y+2)=28(3y-2)

We move all terms to the left:

7(-3y+2)-(28(3y-2))=0

We multiply parentheses

-21y-(28(3y-2))+14=0



We calculate terms in parentheses: -(28(3y-2)), so:

28(3y-2)

We multiply parentheses

84y-56

Back to the equation:

-(84y-56)



We get rid of parentheses

-21y-84y+56+14=0

We add all the numbers together, and all the variables

-105y+70=0

We move all terms containing y to the left, all other terms to the right

-105y=-70

y=-70/-105

y=2/3

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