7(-3y+2)=8(3y+5)

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Solution for 7(-3y+2)=8(3y+5) equation:



7(-3y+2)=8(3y+5)
We move all terms to the left:
7(-3y+2)-(8(3y+5))=0
We multiply parentheses
-21y-(8(3y+5))+14=0
We calculate terms in parentheses: -(8(3y+5)), so:
8(3y+5)
We multiply parentheses
24y+40
Back to the equation:
-(24y+40)
We get rid of parentheses
-21y-24y-40+14=0
We add all the numbers together, and all the variables
-45y-26=0
We move all terms containing y to the left, all other terms to the right
-45y=26
y=26/-45
y=-26/45

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