7(-3y+2)=8(y-2)

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Solution for 7(-3y+2)=8(y-2) equation: 



7(-3y+2)=8(y-2)

We move all terms to the left:

7(-3y+2)-(8(y-2))=0

We multiply parentheses

-21y-(8(y-2))+14=0



We calculate terms in parentheses: -(8(y-2)), so:

8(y-2)

We multiply parentheses

8y-16

Back to the equation:

-(8y-16)



We get rid of parentheses

-21y-8y+16+14=0

We add all the numbers together, and all the variables

-29y+30=0

We move all terms containing y to the left, all other terms to the right

-29y=-30

y=-30/-29

y=1+1/29

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