7(-7-2a)-4a=-3+2(1-3a)

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Solution for 7(-7-2a)-4a=-3+2(1-3a) equation: 



7(-7-2a)-4a=-3+2(1-3a)

We move all terms to the left:

7(-7-2a)-4a-(-3+2(1-3a))=0

We add all the numbers together, and all the variables

7(-2a-7)-4a-(-3+2(-3a+1))=0

We add all the numbers together, and all the variables

-4a+7(-2a-7)-(-3+2(-3a+1))=0

We multiply parentheses

-4a-14a-(-3+2(-3a+1))-49=0



We calculate terms in parentheses: -(-3+2(-3a+1)), so:

-3+2(-3a+1)

determiningTheFunctionDomain
2(-3a+1)-3

We multiply parentheses

-6a+2-3

We add all the numbers together, and all the variables

-6a-1

Back to the equation:

-(-6a-1)



We add all the numbers together, and all the variables

-18a-(-6a-1)-49=0

We get rid of parentheses

-18a+6a+1-49=0

We add all the numbers together, and all the variables

-12a-48=0

We move all terms containing a to the left, all other terms to the right

-12a=48

a=48/-12

a=-4

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