7(-x-11)+4=2(x-10)-161

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Solution for 7(-x-11)+4=2(x-10)-161 equation: 



7(-x-11)+4=2(x-10)-161

We move all terms to the left:

7(-x-11)+4-(2(x-10)-161)=0

We add all the numbers together, and all the variables

7(-1x-11)-(2(x-10)-161)+4=0

We multiply parentheses

-7x-(2(x-10)-161)-77+4=0



We calculate terms in parentheses: -(2(x-10)-161), so:

2(x-10)-161

We multiply parentheses

2x-20-161

We add all the numbers together, and all the variables

2x-181

Back to the equation:

-(2x-181)



We add all the numbers together, and all the variables

-7x-(2x-181)-73=0

We get rid of parentheses

-7x-2x+181-73=0

We add all the numbers together, and all the variables

-9x+108=0

We move all terms containing x to the left, all other terms to the right

-9x=-108

x=-108/-9

x=+12

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