7(1+11a)=21(a-29)

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Solution for 7(1+11a)=21(a-29) equation: 



7(1+11a)=21(a-29)

We move all terms to the left:

7(1+11a)-(21(a-29))=0

We add all the numbers together, and all the variables

7(11a+1)-(21(a-29))=0

We multiply parentheses

77a-(21(a-29))+7=0



We calculate terms in parentheses: -(21(a-29)), so:

21(a-29)

We multiply parentheses

21a-609

Back to the equation:

-(21a-609)



We get rid of parentheses

77a-21a+609+7=0

We add all the numbers together, and all the variables

56a+616=0

We move all terms containing a to the left, all other terms to the right

56a=-616

a=-616/56

a=-11

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