7(1+3x)+1=3(-3+2x)*2

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Solution for 7(1+3x)+1=3(-3+2x)*2 equation: 



7(1+3x)+1=3(-3+2x)*2

We move all terms to the left:

7(1+3x)+1-(3(-3+2x)*2)=0

We add all the numbers together, and all the variables

7(3x+1)-(3(2x-3)*2)+1=0

We multiply parentheses

21x-(3(2x-3)*2)+7+1=0



We calculate terms in parentheses: -(3(2x-3)*2), so:

3(2x-3)*2

We multiply parentheses

12x-18

Back to the equation:

-(12x-18)



We add all the numbers together, and all the variables

21x-(12x-18)+8=0

We get rid of parentheses

21x-12x+18+8=0

We add all the numbers together, and all the variables

9x+26=0

We move all terms containing x to the left, all other terms to the right

9x=-26

x=-26/9

x=-2+8/9

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