7(1+4b)=5+2(7b+1)

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Solution for 7(1+4b)=5+2(7b+1) equation:



7(1+4b)=5+2(7b+1)
We move all terms to the left:
7(1+4b)-(5+2(7b+1))=0
We add all the numbers together, and all the variables
7(4b+1)-(5+2(7b+1))=0
We multiply parentheses
28b-(5+2(7b+1))+7=0
We calculate terms in parentheses: -(5+2(7b+1)), so:
5+2(7b+1)
determiningTheFunctionDomain 2(7b+1)+5
We multiply parentheses
14b+2+5
We add all the numbers together, and all the variables
14b+7
Back to the equation:
-(14b+7)
We get rid of parentheses
28b-14b-7+7=0
We add all the numbers together, and all the variables
14b=0
b=0/14
b=0

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