7(1+6y)=35

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Solution for 7(1+6y)=35 equation: 



7(1+6y)=35

We move all terms to the left:

7(1+6y)-(35)=0

We add all the numbers together, and all the variables

7(6y+1)-35=0

We multiply parentheses

42y+7-35=0

We add all the numbers together, and all the variables

42y-28=0

We move all terms containing y to the left, all other terms to the right

42y=28

y=28/42

y=2/3

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