7(1+C)=6(C-2)

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Solution for 7(1+C)=6(C-2) equation: 


Simplifying
7(1 + C) = 6(C + -2)
(1 * 7 + C * 7) = 6(C + -2)
(7 + 7C) = 6(C + -2)

Reorder the terms:
7 + 7C = 6(-2 + C)
7 + 7C = (-2 * 6 + C * 6)
7 + 7C = (-12 + 6C)

Solving
7 + 7C = -12 + 6C

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-6C' to each side of the equation.
7 + 7C + -6C = -12 + 6C + -6C

Combine like terms: 7C + -6C = 1C
7 + 1C = -12 + 6C + -6C

Combine like terms: 6C + -6C = 0
7 + 1C = -12 + 0
7 + 1C = -12

Add '-7' to each side of the equation.
7 + -7 + 1C = -12 + -7

Combine like terms: 7 + -7 = 0
0 + 1C = -12 + -7
1C = -12 + -7

Combine like terms: -12 + -7 = -19
1C = -19

Divide each side by '1'.
C = -19

Simplifying
C = -19

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