7(1+b)+5(7-b)=40

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Solution for 7(1+b)+5(7-b)=40 equation: 



7(1+b)+5(7-b)=40

We move all terms to the left:

7(1+b)+5(7-b)-(40)=0

We add all the numbers together, and all the variables

7(b+1)+5(-1b+7)-40=0

We multiply parentheses

7b-5b+7+35-40=0

We add all the numbers together, and all the variables

2b+2=0

We move all terms containing b to the left, all other terms to the right

2b=-2

b=-2/2

b=-1

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