7(1+c)=6(c-1)

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Solution for 7(1+c)=6(c-1) equation:


Simplifying
7(1 + c) = 6(c + -1)
(1 * 7 + c * 7) = 6(c + -1)
(7 + 7c) = 6(c + -1)

Reorder the terms:
7 + 7c = 6(-1 + c)
7 + 7c = (-1 * 6 + c * 6)
7 + 7c = (-6 + 6c)

Solving
7 + 7c = -6 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
7 + 7c + -6c = -6 + 6c + -6c

Combine like terms: 7c + -6c = 1c
7 + 1c = -6 + 6c + -6c

Combine like terms: 6c + -6c = 0
7 + 1c = -6 + 0
7 + 1c = -6

Add '-7' to each side of the equation.
7 + -7 + 1c = -6 + -7

Combine like terms: 7 + -7 = 0
0 + 1c = -6 + -7
1c = -6 + -7

Combine like terms: -6 + -7 = -13
1c = -13

Divide each side by '1'.
c = -13

Simplifying
c = -13

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