7(1+n)+8(3n-4)=68

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Solution for 7(1+n)+8(3n-4)=68 equation:



7(1+n)+8(3n-4)=68
We move all terms to the left:
7(1+n)+8(3n-4)-(68)=0
We add all the numbers together, and all the variables
7(n+1)+8(3n-4)-68=0
We multiply parentheses
7n+24n+7-32-68=0
We add all the numbers together, and all the variables
31n-93=0
We move all terms containing n to the left, all other terms to the right
31n=93
n=93/31
n=3

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