7(1+p)-1=3p-2+4(p+2)

Solution for 7(1+p)-1=3p-2+4(p+2) equation:

Simplifying
7(1 + p) + -1 = 3p + -2 + 4(p + 2)
(1 * 7 + p * 7) + -1 = 3p + -2 + 4(p + 2)
(7 + 7p) + -1 = 3p + -2 + 4(p + 2)

Reorder the terms:
7 + -1 + 7p = 3p + -2 + 4(p + 2)

Combine like terms: 7 + -1 = 6
6 + 7p = 3p + -2 + 4(p + 2)

Reorder the terms:
6 + 7p = 3p + -2 + 4(2 + p)
6 + 7p = 3p + -2 + (2 * 4 + p * 4)
6 + 7p = 3p + -2 + (8 + 4p)

Reorder the terms:
6 + 7p = -2 + 8 + 3p + 4p

Combine like terms: -2 + 8 = 6
6 + 7p = 6 + 3p + 4p

Combine like terms: 3p + 4p = 7p
6 + 7p = 6 + 7p

Add '-6' to each side of the equation.
6 + -6 + 7p = 6 + -6 + 7p

Combine like terms: 6 + -6 = 0
0 + 7p = 6 + -6 + 7p
7p = 6 + -6 + 7p

Combine like terms: 6 + -6 = 0
7p = 0 + 7p
7p = 7p

Add '-7p' to each side of the equation.
7p + -7p = 7p + -7p

Combine like terms: 7p + -7p = 0
0 = 7p + -7p

Combine like terms: 7p + -7p = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.