7(1-3)+n=6-(n-4)

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Solution for 7(1-3)+n=6-(n-4) equation: 



7(1-3)+n=6-(n-4)

We move all terms to the left:

7(1-3)+n-(6-(n-4))=0

We add all the numbers together, and all the variables

n-(6-(n-4))+7(-2)=0

We add all the numbers together, and all the variables

n-(6-(n-4))-14=0



We calculate terms in parentheses: -(6-(n-4)), so:

6-(n-4)

determiningTheFunctionDomain
-(n-4)+6

We get rid of parentheses

-n+4+6

We add all the numbers together, and all the variables

-1n+10

Back to the equation:

-(-1n+10)



We get rid of parentheses

n+1n-10-14=0

We add all the numbers together, and all the variables

2n-24=0

We move all terms containing n to the left, all other terms to the right

2n=24

n=24/2

n=12

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