7(1-7)=-3(y-2)

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Solution for 7(1-7)=-3(y-2) equation: 



7(1-7)=-3(y-2)

We move all terms to the left:

7(1-7)-(-3(y-2))=0

We add all the numbers together, and all the variables

-(-3(y-2))+7(-6)=0

We add all the numbers together, and all the variables

-(-3(y-2))-42=0



We calculate terms in parentheses: -(-3(y-2)), so:

-3(y-2)

We multiply parentheses

-3y+6

Back to the equation:

-(-3y+6)



We get rid of parentheses

3y-6-42=0

We add all the numbers together, and all the variables

3y-48=0

We move all terms containing y to the left, all other terms to the right

3y=48

y=48/3

y=16

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