7(1-x)=3(x-2)

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Solution for 7(1-x)=3(x-2) equation: 



7(1-x)=3(x-2)

We move all terms to the left:

7(1-x)-(3(x-2))=0

We add all the numbers together, and all the variables

7(-1x+1)-(3(x-2))=0

We multiply parentheses

-7x-(3(x-2))+7=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

-7x-3x+6+7=0

We add all the numbers together, and all the variables

-10x+13=0

We move all terms containing x to the left, all other terms to the right

-10x=-13

x=-13/-10

x=1+3/10

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