7(1-y)=-(3y-2)

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Solution for 7(1-y)=-(3y-2) equation: 



7(1-y)=-(3y-2)

We move all terms to the left:

7(1-y)-(-(3y-2))=0

We add all the numbers together, and all the variables

7(-1y+1)-(-(3y-2))=0

We multiply parentheses

-7y-(-(3y-2))+7=0



We calculate terms in parentheses: -(-(3y-2)), so:

-(3y-2)

We get rid of parentheses

-3y+2

Back to the equation:

-(-3y+2)



We get rid of parentheses

-7y+3y-2+7=0

We add all the numbers together, and all the variables

-4y+5=0

We move all terms containing y to the left, all other terms to the right

-4y=-5

y=-5/-4

y=1+1/4

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