7(1-y)=-3(y+2)

Solution for 7(1-y)=-3(y+2) equation:

7(1-y)=-3(y+2)

We move all terms to the left:

7(1-y)-(-3(y+2))=0

We add all the numbers together, and all the variables

7(-1y+1)-(-3(y+2))=0

We multiply parentheses

-7y-(-3(y+2))+7=0


We calculate terms in parentheses: -(-3(y+2)), so:

-3(y+2)

We multiply parentheses

-3y-6

Back to the equation:

-(-3y-6)


We get rid of parentheses

-7y+3y+6+7=0

We add all the numbers together, and all the variables

-4y+13=0

We move all terms containing y to the left, all other terms to the right

-4y=-13

y=-13/-4

y=3+1/4