7(1-y)=-39(y-2)

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Solution for 7(1-y)=-39(y-2) equation: 



7(1-y)=-39(y-2)

We move all terms to the left:

7(1-y)-(-39(y-2))=0

We add all the numbers together, and all the variables

7(-1y+1)-(-39(y-2))=0

We multiply parentheses

-7y-(-39(y-2))+7=0



We calculate terms in parentheses: -(-39(y-2)), so:

-39(y-2)

We multiply parentheses

-39y+78

Back to the equation:

-(-39y+78)



We get rid of parentheses

-7y+39y-78+7=0

We add all the numbers together, and all the variables

32y-71=0

We move all terms containing y to the left, all other terms to the right

32y=71

y=71/32

y=2+7/32

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