7(1-y)=3-(y-2)

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Solution for 7(1-y)=3-(y-2) equation: 



7(1-y)=3-(y-2)

We move all terms to the left:

7(1-y)-(3-(y-2))=0

We add all the numbers together, and all the variables

7(-1y+1)-(3-(y-2))=0

We multiply parentheses

-7y-(3-(y-2))+7=0



We calculate terms in parentheses: -(3-(y-2)), so:

3-(y-2)

determiningTheFunctionDomain
-(y-2)+3

We get rid of parentheses

-y+2+3

We add all the numbers together, and all the variables

-1y+5

Back to the equation:

-(-1y+5)



We get rid of parentheses

-7y+1y-5+7=0

We add all the numbers together, and all the variables

-6y+2=0

We move all terms containing y to the left, all other terms to the right

-6y=-2

y=-2/-6

y=1/3

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