7(1750-35y/3)+6y=3800

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Solution for 7(1750-35y/3)+6y=3800 equation:



7(1750-35y/3)+6y=3800
We move all terms to the left:
7(1750-35y/3)+6y-(3800)=0
We add all the numbers together, and all the variables
7(-35y/3+1750)+6y-3800=0
We add all the numbers together, and all the variables
6y+7(-35y/3+1750)-3800=0
We multiply parentheses
6y-245y+12250-3800=0
We add all the numbers together, and all the variables
-239y+8450=0
We move all terms containing y to the left, all other terms to the right
-239y=-8450
y=-8450/-239
y=35+85/239

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