7(1x-4)-3=-5(2-x)+10(x+4)

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Solution for 7(1x-4)-3=-5(2-x)+10(x+4) equation: 



7(1x-4)-3=-5(2-x)+10(x+4)

We move all terms to the left:

7(1x-4)-3-(-5(2-x)+10(x+4))=0

We add all the numbers together, and all the variables

7(x-4)-(-5(-1x+2)+10(x+4))-3=0

We multiply parentheses

7x-(-5(-1x+2)+10(x+4))-28-3=0



We calculate terms in parentheses: -(-5(-1x+2)+10(x+4)), so:

-5(-1x+2)+10(x+4)

We multiply parentheses

5x+10x-10+40

We add all the numbers together, and all the variables

15x+30

Back to the equation:

-(15x+30)



We add all the numbers together, and all the variables

7x-(15x+30)-31=0

We get rid of parentheses

7x-15x-30-31=0

We add all the numbers together, and all the variables

-8x-61=0

We move all terms containing x to the left, all other terms to the right

-8x=61

x=61/-8

x=-7+5/8

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