7(1y+-2)+8=3(1y+-4)+-2

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Solution for 7(1y+-2)+8=3(1y+-4)+-2 equation:


Simplifying
7(1y + -2) + 8 = 3(1y + -4) + -2

Reorder the terms:
7(-2 + 1y) + 8 = 3(1y + -4) + -2
(-2 * 7 + 1y * 7) + 8 = 3(1y + -4) + -2
(-14 + 7y) + 8 = 3(1y + -4) + -2

Reorder the terms:
-14 + 8 + 7y = 3(1y + -4) + -2

Combine like terms: -14 + 8 = -6
-6 + 7y = 3(1y + -4) + -2

Reorder the terms:
-6 + 7y = 3(-4 + 1y) + -2
-6 + 7y = (-4 * 3 + 1y * 3) + -2
-6 + 7y = (-12 + 3y) + -2

Reorder the terms:
-6 + 7y = -12 + -2 + 3y

Combine like terms: -12 + -2 = -14
-6 + 7y = -14 + 3y

Solving
-6 + 7y = -14 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-6 + 7y + -3y = -14 + 3y + -3y

Combine like terms: 7y + -3y = 4y
-6 + 4y = -14 + 3y + -3y

Combine like terms: 3y + -3y = 0
-6 + 4y = -14 + 0
-6 + 4y = -14

Add '6' to each side of the equation.
-6 + 6 + 4y = -14 + 6

Combine like terms: -6 + 6 = 0
0 + 4y = -14 + 6
4y = -14 + 6

Combine like terms: -14 + 6 = -8
4y = -8

Divide each side by '4'.
y = -2

Simplifying
y = -2

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