7(2+4h)=6(3h+5)

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Solution for 7(2+4h)=6(3h+5) equation: 



7(2+4h)=6(3h+5)

We move all terms to the left:

7(2+4h)-(6(3h+5))=0

We add all the numbers together, and all the variables

7(4h+2)-(6(3h+5))=0

We multiply parentheses

28h-(6(3h+5))+14=0



We calculate terms in parentheses: -(6(3h+5)), so:

6(3h+5)

We multiply parentheses

18h+30

Back to the equation:

-(18h+30)



We get rid of parentheses

28h-18h-30+14=0

We add all the numbers together, and all the variables

10h-16=0

We move all terms containing h to the left, all other terms to the right

10h=16

h=16/10

h=1+3/5

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