7(2+c)=21(c-4)

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Solution for 7(2+c)=21(c-4) equation: 



7(2+c)=21(c-4)

We move all terms to the left:

7(2+c)-(21(c-4))=0

We add all the numbers together, and all the variables

7(c+2)-(21(c-4))=0

We multiply parentheses

7c-(21(c-4))+14=0



We calculate terms in parentheses: -(21(c-4)), so:

21(c-4)

We multiply parentheses

21c-84

Back to the equation:

-(21c-84)



We get rid of parentheses

7c-21c+84+14=0

We add all the numbers together, and all the variables

-14c+98=0

We move all terms containing c to the left, all other terms to the right

-14c=-98

c=-98/-14

c=+7

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